CardRowSelectorViewModel - конструктор |
Пространство имён:
Tessa.UI.Cards.Controls
Сборка:
Tessa.UI (в Tessa.UI.dll) Версия: 3.5.0.19
Синтаксисpublic CardRowSelectorViewModel(
IList<CardRow> itemsSource,
Card card,
CardColumnInfo[] columnInfoArray,
Func<CardRow, int> getOrder,
GridViewModel control,
IMenuContext menuContext,
ViewModelScope scope
)
Public Sub New (
itemsSource As IList(Of CardRow),
card As Card,
columnInfoArray As CardColumnInfo(),
getOrder As Func(Of CardRow, Integer),
control As GridViewModel,
menuContext As IMenuContext,
scope As ViewModelScope
)
public:
CardRowSelectorViewModel(
IList<CardRow^>^ itemsSource,
Card^ card,
array<CardColumnInfo^>^ columnInfoArray,
Func<CardRow^, int>^ getOrder,
GridViewModel^ control,
IMenuContext^ menuContext,
ViewModelScope^ scope
)
new :
itemsSource : IList<CardRow> *
card : Card *
columnInfoArray : CardColumnInfo[] *
getOrder : Func<CardRow, int> *
control : GridViewModel *
menuContext : IMenuContext *
scope : ViewModelScope -> CardRowSelectorViewModel
Параметры
- itemsSource
- Тип: System.Collections.Generic.IList<CardRow>
- card
- Тип: Tessa.Cards.Card
- columnInfoArray
- Тип:Tessa.UI.Cards.Controls.CardColumnInfo[]
- getOrder
- Тип: System.Func<CardRow, Int32>
- control
- Тип: Tessa.UI.Cards.Controls.GridViewModel
- menuContext
- Тип: Tessa.UI.Menu.IMenuContext
- scope
- Тип: Tessa.UI.ViewModelScope
См. также